By Wegner F.
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Can be "asymptotically integrable", that's to assert, if we displace a vector parallel to itself alongside a closed curve whose overall size is proportional to r, then, as we eliminate the curve to infinity, the switch of the vector that effects from the circuit in regards to the curve will are inclined to 0. within the presence of gravitational radiation the complete strength should not con served, as the waves hold a few strength with them; analogous statements practice to the linear momentum, and so on.
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Extra info for Classical electrodynamics - Klassische Elektrodynamik
14) has been applied. 20) 1 . 21) and div j2 (r) = 0, one obtains finally for the force d3 rd3 r j1 (r ) · j2 (r) ∇ Die auf den ersten Stromkreis wirkende Kraft erh¨alt man durch Austauschen von 1 und 2. Gleichzeitig kann man r und r austauschen. Man sieht dann, dass The force acting on circuit (1) is obtained by exchanging 1 and 2. Simultaneously, one can exchange r and r . 22) gilt. holds. Aufgabe Berechne die Kraft zwischen zwei von Str¨omen I1 und I2 durchlaufenen Dr¨ahten, die u¨ ber die L¨ange l parallel im Abstand r (r l) laufen.
Man sieht dann, dass The force acting on circuit (1) is obtained by exchanging 1 and 2. Simultaneously, one can exchange r and r . 22) gilt. holds. Aufgabe Berechne die Kraft zwischen zwei von Str¨omen I1 und I2 durchlaufenen Dr¨ahten, die u¨ ber die L¨ange l parallel im Abstand r (r l) laufen. Hieraus bestimmten K und W die Lichtgeschwindigkeit. Exercise Calculate the force between two wires of length l carrying currents I1 and I2 which run parallel in a distance r (r l). K and W measured this force in order to determine the velocity of light.
The field between two charges q and −q at r2 and r1 is equivalent to a line of electric dipoles dp = qdr from r = r1 to r = r2 . 12) and thus for the field E(r) = q r − r2 r − r1 . 14) dm = dl c lc zusammengesetzt zu denken. Ber¨ucksichtigen wir, . 12) ausser except at the point of the dipole, then it follows that am Ort des Dipols, so folgt, in dem wir q durch we may replace q by qm = NI f /(lc) in order to obtain qm = NI f /(lc) ersetzen, die magnetische Induktion the magnetic induction r − r2 r − r1 B(r) = qm .
Classical electrodynamics - Klassische Elektrodynamik by Wegner F.